# hydrogen gas formula

At the identical temperature and pressure, the rate of diffusion of hydrogen gas is 3√3 times that of a hydrocarbon having molecular formula CnH2n−2. What is the volume of n? » Click here👆to get an answer to your question ✍️ at the identical temperature and pressure the rate of diffusion of hydrogen gas is sqrt Toppr.com

Dalton's law of partial pressure (article) | Khan Academy » Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere. Khanacademy.org

6.3: Combining the Gas Laws: The Ideal Gas Equation and the General Gas Equation » Jul 12, 2023…… calculate the number of moles of hydrogen gas needed. Solution: A We… If we solve the ideal gas law (Equation 6.3.4) for n, we obtain. 745m … Chem.libretexts.org

3.2 Determining Empirical and Molecular Formulas - Chemistry 2e | OpenStax » The elemental makeup of a compound defines its chemical identity, and chemical formulas are the most succinct way of representing this elemental makeup…. Openstax.org

9.2 Relating Pressure, Volume, Amount, and Temperature: The Ideal Gas Law - Chemistry 2e | OpenStax » Imagine filling a rigid container attached to a pressure gauge with gas and then sealing the container so that no gas may escape. If the container is co… Openstax.org

How can I balance this equation? _ N2 + _ H2 ---> ____ NH3 | Socratic » This reaction is the synthesis of Ammonia using Nitrogen and Hydrogen gas. N + H -> NH_3 We must remember that Nitrogen and Hydrogen are both diatomic molecules in their standard gas form. This adjusts the equation to N_2 + H_2 -> NH_3 Now we need to adjust coefficients in order to balance the atoms on each side of the equation. Currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side. We can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen. N_2 + 3H_2 -> 2NH_3 This gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side. I hope this was helpful. SMARTERTEACHER Socratic.org